What is the molarity of a solution created by mixing 0.25 moles of CuSO4 with 192 ml of water?

To determine the molarity of the solution formed by mixing 0.25 moles of CuSO4 with 192 mL of water, we first need to understand the concept of molarity, which is defined as the number of moles of solute divided by the volume of the solution in liters.

1. Calculate the total volume of the solution in liters. Since the volume given is in milliliters, we need to convert 192 mL to liters:

[

192 , \text{mL} \times \frac{1 , \text{L}}{1000 , \text{mL}} = 0.192 , \text{L}

]

2. Using the formula for molarity ( M = \frac{\text{moles of solute}}{\text{liters of solution}} ):

[

M = \frac{0.25 , \text{moles}}{0.192 , \text{L}} \approx 1.3021 , \text{M}

]

3. Rounding the calculated molarity to two decimal places gives approximately 1.30 M.

The value